return to the Course index
previous | next
Since
and
then
or
taking the ln of both sides
Thus
Thus the approach to Cpss is exponential in nature and is controlled by the elimination process NOT the infusion process. NOTE however that the value of Cpss IS controlled by k0.
Halfway - 50% | to steady state | in | one | half-life |
75% | to steady state | in | 2 | half-life |
87.5% | to steady state | in | 3 | half-life |
94% | to steady state | in | 4 | half-life |
For theophylline with a t1/2 equal to 4 hours the time to reach 94% of steady state will be 16 hours. We could calculate how long it might take to reach a therapeutic concentration. For theophylline this might be 10 mg/L
Thus
Using the values from before
k0 = 60 mg/hr; kel = 0.17 hr- 1; V = 25 L; and Crequired = 10 mg/L
thus
and taking the ln of both sides gives -0.17 * t = -1.231 or t = 7.24 hr
Thus if we started an infusion to achieve a steady state plasma concentration of approximately 15 mg/L (actually 14.1 mg/L) it would take 7.25 hours to reach a therapeutic level of 10 mg/L. This is probably too long so another strategy should be explored.
Material on this website should be used for Educational or Self-Study Purposes Only
Copyright © 2001 - 2025 David W. A. Bourne (david@boomer.org)
![]() | A game to aid recognizing drug structures See how many structures you can name before you run out of lives |
![]() |